\(15,05-y\times3-y\times7=3,05\\ 15.05-\left[y\times\left(3+7\right)\right]=3,05\\ 15,05-y\times10=3,05\\ y\times10=15,05-3,05\\ y\times10=12\\ y=12:10\\ y=1,2\)
Vậy y=1,2
15,05-Yx3-Yx7=3.05
<=> 15,05-3,05=Yx3+Yx7
<=>12=Y(3+7)
=> Y = 1,2
`15,05 - y xx 3 - y xx 7 = 3,05`
`15,05 - yxx(3+7)=3,05`
`15,05 - y xx 10 = 3,05`
`y xx 10 = 15,05-3,05`
`y xx 10 = 12`
`y=12:10`
`y=1,2`