Question

Mình cần gấp ạ ,giúp tớ với Cảm ơn rất nhiều

Answer 1

Dạng 3 

Bài 1

\(1,2x\left(x-6\right)-x+6=0\\ \Rightarrow2x\left(x-6\right)-\left(x-6\right)=0\\ \Rightarrow\left(2x-1\right)\left(x-6\right)=0\\ \Rightarrow\left[{}\begin{matrix}x-6=0\\2x-1=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=6\\x=\dfrac{1}{2}\end{matrix}\right.\)

\(2,13x^2-5x=0\\ \Rightarrow x\left(13x-5\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=0\\13x-5=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\\x=\dfrac{5}{13}\end{matrix}\right.\)

\(3,4x^2-25=0\\ \Rightarrow\left(2x-5\right)\left(2x+5\right)=0\\ \Rightarrow\left[{}\begin{matrix}2x-5=0\\2x+5=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{5}{2}\\x=-\dfrac{5}{2}\end{matrix}\right.\)

\(4,4x^2-16x=0\\ \Rightarrow4x\left(x-4\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=4\end{matrix}\right.\)

Bài 2

\(a,4x^2-12x=0\\ \Rightarrow4x\left(x-3\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=0\\x-3=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=3\end{matrix}\right.\)

\(b,2x^2-6x=0\\ \Rightarrow2x\left(x-3\right)=0\\ \Rightarrow\left[{}\begin{matrix}2x=0\\x-3=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=3\end{matrix}\right.\)

\(c,x\left(x-2\right)+x-2=0\\ \Rightarrow\left(x+1\right)\left(x-2\right)=0\\ \Rightarrow\left[{}\begin{matrix}x+1=0\\x-2=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\)

\(d,x\left(x-5\right)+x-5=0\\ \Rightarrow\left(x+1\right)\left(x-5\right)=0\\ \Rightarrow\left[{}\begin{matrix}x+1=0\\x-5=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-1\\x=5\end{matrix}\right.\)

\(e,4x\left(x-2\right)-x+2=0\\ \Rightarrow4x\left(x-2\right)-\left(x-2\right)=0\\ \Rightarrow\left(4x-1\right)\left(x-2\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{4}\\x=2\end{matrix}\right.\)

\(h,2x\left(x-5\right)-x+5=0\\ \Rightarrow2x\left(x-5\right)-\left(x-5\right)=0\\ \Rightarrow\left(2x-1\right)\left(x-5\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=5\\x=\dfrac{1}{2}\end{matrix}\right.\\ g,x\left(x-3\right)-2x+6=0\\ \Rightarrow x\left(x-3\right)-2\left(x-3\right)=0\\ \Rightarrow\left(x-2\right)\left(x-3\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=2\\x=3\end{matrix}\right.\\ Goodnight:>\)

Answer 2

bài 1

1)

 \(2x\left(x-6\right)-x+6=0\\ 2x\left(x-6\right)-\left(x-6\right)=0\\ \left(2x-1\right)\left(x-6\right)=0\\ \left[{}\begin{matrix}2x-1=0\\x-6=0\end{matrix}\right.\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=6\end{matrix}\right.\)

2)

 \(x\left(13x-5\right)=0\\ \left[{}\begin{matrix}x=0\\13x-5=0\end{matrix}\right.\left[{}\begin{matrix}x=0\\x=\dfrac{5}{13}\end{matrix}\right.\)

3) 

\(\left(2x-5\right)\left(2x+5\right)=0\\ \left[{}\begin{matrix}2x-5=0\\2x+5=0\end{matrix}\right.\left[{}\begin{matrix}x=\dfrac{5}{2}\\x=-\dfrac{5}{2}\end{matrix}\right.\)

4)

\(4x\left(x-4\right)=0\\ \left[{}\begin{matrix}4x=0\\x-4=0\end{matrix}\right.\left[{}\begin{matrix}x=0\\x=4\end{matrix}\right.\)

bài 2

a)

\(4x\left(x-3\right)=0\\ \left[{}\begin{matrix}4x=0\\x-3\end{matrix}\right.\left[{}\begin{matrix}x=0\\x=3\end{matrix}\right.\)

b)

\(2x\left(x-3\right)=0\\ \left[{}\begin{matrix}2x=0\\x-3=0\end{matrix}\right.\left[{}\begin{matrix}x=0\\x=3\end{matrix}\right.\)

c)

\(x\left(x-2\right)+\left(x-2\right)=0\\ \left(x-2\right)\left(x+1\right)=0\\ \left[{}\begin{matrix}x-2=0\\x+1=0\end{matrix}\right.\left[{}\begin{matrix}x=2\\x=-1\end{matrix}\right.\)

d)

\(x\left(x-5\right)+\left(x-5\right)=0\\ \left(x-5\right)\left(x+1\right)=0\\ \left[{}\begin{matrix}x-5=0\\x+1=0\end{matrix}\right.\left[{}\begin{matrix}x=5\\x=-1\end{matrix}\right.\)

e)

\(4x\left(x-2\right)-\left(x-2\right)=0\\ \left(x-2\right)\left(4x-1\right)=0\\ \left[{}\begin{matrix}x-2=0\\4x-1=0\end{matrix}\right.\left[{}\begin{matrix}x=2\\x=\dfrac{1}{4}\end{matrix}\right.\)

h)

\(2x\left(x-5\right)-\left(x-5\right)=0\\ \left(x-5\right)\left(2x-1\right)=0\\ \left[{}\begin{matrix}x-5=0\\2x-1=0\end{matrix}\right.\left[{}\begin{matrix}x=5\\x=\dfrac{1}{2}\end{matrix}\right.\)

g)

\(x\left(x-3\right)-2\left(x-3\right)=0\\ \left(x-3\right)\left(x-2\right)=0\\ \left[{}\begin{matrix}x-3=0\\x-2=0\end{matrix}\right.\left[{}\begin{matrix}x=3\\x=2\end{matrix}\right.\)