\(4^3\cdot2^{x+1}=1\)
\(\Leftrightarrow2^{x+1}=\dfrac{1}{64}\)
\(\Leftrightarrow x+1=-6\)
hay x=-7
26 . 2x+1 = 1
26(x + 1) = 20
6(x+1)=0
x+1=-6
x=-7
`4^3 . 2^(x+1) = 1`
`<=> 64 . 2^(x+1) =1`
`<=> 2^(x+1) = 1:64`
`<=> 2^(x+1) = 1/64`
`<=>2^(x+1) = (1/2)^6`
`<=> x+1 = 6`
`<=> x = 6-1`
`<=>x=5`