\(\Leftrightarrow3\left(x+2\right):7=30\)
=>3(x+2)=210
=>x+2=70
hay x=68
\(\left[3\cdot\left(x+2\right)\div7\right]\cdot4=120\)
\(3\cdot\left(x+2\right)\div7=120\div4\)
\(3\cdot\left(x+2\right)\div7=30\)
\(3\left(x+2\right)=30\cdot7\)
\(3\cdot\left(x+2\right)=210\)
x+2=210:3
x+2=70
x=68