18 tháng 1 2022 lúc 13:38
Các câu hỏi tương tự
a) dfrac{12}{16} dfrac{-x}{4} dfrac{21}{y} dfrac{z}{80} b) dfrac{1}{3} x + dfrac{2}{5} ( x - 1 ) 0c) ( 2x - 3 )( 6 - 2x ) 0d) dfrac{-2}{3} - dfrac{1}{3} ( 2x - 5 ) dfrac{3}{2}e) 2 |dfrac{1}{2} x - dfrac{1}{3} | - dfrac{1}{4}
Đọc tiếp
a) \(\dfrac{12}{16}\) = \(\dfrac{-x}{4}\) = \(\dfrac{21}{y}\) = \(\dfrac{z}{80}\)
b) \(\dfrac{1}{3}\) x + \(\dfrac{2}{5}\) ( x - 1 ) = 0
c) ( 2x - 3 )( 6 - 2x ) = 0
d) \(\dfrac{-2}{3}\) - \(\dfrac{1}{3}\) ( 2x - 5 ) = \(\dfrac{3}{2}\)
e) 2 |\(\dfrac{1}{2}\) x - \(\dfrac{1}{3}\) | - \(\dfrac{1}{4}\)
29 tháng 1 2022 lúc 11:20
Tìm x biết:a,3dfrac{1}{2}-dfrac{1}{2}xdfrac{2}{3}b,dfrac{1}{3}+dfrac{2}{3}:x-7c,dfrac{1}{3}x+dfrac{2}{5}left(x-1right)0d,left(2x-3right)left(6-2xright)0e,x:dfrac{3}{4}+dfrac{1}{4}-dfrac{2}{3}f,dfrac{-2}{3}-dfrac{1}{3}left(2x-5right)dfrac{3}{2}g,2left|dfrac{1}{2}x-dfrac{1}{3}right|-dfrac{3}{2}dfrac{1}{4}h,dfrac{3}{4}-2.left|2x-dfrac{2}{3}right|2i,left(-0,6x-dfrac{1}{2}right).dfrac{3}{4}-left(-1right)dfrac{1}{3}j,left(3x-1right)left(-dfrac{1}{2}x+5right)0k,dfrac{1}{4}+dfrac{1}{3}:left(2x-1right)-5...
Đọc tiếp
Tìm x biết:
\(a,3\dfrac{1}{2}-\dfrac{1}{2}x=\dfrac{2}{3}\)
\(b,\dfrac{1}{3}+\dfrac{2}{3}:x=-7\)
\(c,\dfrac{1}{3}x+\dfrac{2}{5}\left(x-1\right)=0\)
\(d,\left(2x-3\right)\left(6-2x\right)=0\)
\(e,x:\dfrac{3}{4}+\dfrac{1}{4}=-\dfrac{2}{3}\)
\(f,\dfrac{-2}{3}-\dfrac{1}{3}\left(2x-5\right)=\dfrac{3}{2}\)
\(g,2\left|\dfrac{1}{2}x-\dfrac{1}{3}\right|-\dfrac{3}{2}=\dfrac{1}{4}\)
\(h,\dfrac{3}{4}-2.\left|2x-\dfrac{2}{3}\right|=2\)
\(i,\left(-0,6x-\dfrac{1}{2}\right).\dfrac{3}{4}-\left(-1\right)=\dfrac{1}{3}\)
\(j,\left(3x-1\right)\left(-\dfrac{1}{2}x+5\right)=0\)
\(k,\dfrac{1}{4}+\dfrac{1}{3}:\left(2x-1\right)=-5\)
\(l,\left(2x+\dfrac{3}{5}\right)^2-\dfrac{9}{25}=0\)
\(m,3\left(3x-\dfrac{1}{2}\right)^3+\dfrac{1}{9}=0\)
\(n,60\%x+\dfrac{2}{3}x=\dfrac{1}{3}.6\dfrac{1}{3}\)
\(p,-5\left(x+\dfrac{1}{5}\right)-\dfrac{1}{2}\left(x-\dfrac{2}{3}\right)=\dfrac{3}{2}x-\dfrac{5}{6}\)
\(q,3\left(x-\dfrac{1}{2}\right)-5\left(x+\dfrac{3}{5}\right)=-x+\dfrac{1}{5}\)
4 tháng 5 2022 lúc 17:23
x \(\dfrac{2}{3}\)=\(\dfrac{1}{5}\)
\(\dfrac{2}{x}\)=\(\dfrac{12}{5}\)
\(\dfrac{1}{2}\)x-\(\dfrac{3}{5}\)=\(\dfrac{-4}{5}\)
3x+2x=-5,05
12 tháng 5 2021 lúc 8:38
text{Tìm x, biết:}a) 20text{%}x-x+dfrac{1}{5}dfrac{3}{4}b) dfrac{2x+1}{3}dfrac{x-5}{2}c) left(x-dfrac{3}{4}right)left(4+3xright)0d) x-dfrac{1}{3}x+dfrac{1}{5}xdfrac{-26}{5}e) 50text{%}x+dfrac{2}{3}xx-5g) dfrac{2}{3}left(x+dfrac{9}{5}right)-dfrac{3}{10}.left(5x-dfrac{1}{3}right)dfrac{7}{15}
Đọc tiếp
\(\text{Tìm x, biết:}\)
\(a\)) \(20\text{%}x-x+\dfrac{1}{5}=\dfrac{3}{4}\)
\(b\)) \(\dfrac{2x+1}{3}=\dfrac{x-5}{2}\)
\(c\)) \(\left(x-\dfrac{3}{4}\right)\left(4+3x\right)=0\)
\(d\)) \(x-\dfrac{1}{3}x+\dfrac{1}{5}x=\dfrac{-26}{5}\)
\(e\)) \(50\text{%}x+\dfrac{2}{3}x=x-5\)
\(g\)) \(\dfrac{2}{3}\left(x+\dfrac{9}{5}\right)-\dfrac{3}{10}.\left(5x-\dfrac{1}{3}\right)=\dfrac{7}{15}\)
11 tháng 7 2023 lúc 9:25
Tìm x:
a) \(\dfrac{5}{4}+\left(2x-\dfrac{1}{2}\right)=\dfrac{5}{6}\)
b) \(\dfrac{3}{2}-\left(x+\dfrac{1}{4}\right)=\dfrac{5}{8}\)
c) \(\dfrac{x}{3}=\dfrac{12}{x}\)
Giúp với!
12 tháng 5 2021 lúc 16:06
dfrac{-7}{x}text{}dfrac{-21}{x-34} dfrac{4-x}{-5}text{}dfrac{-5}{4-x} dfrac{3}{x+2}text{}dfrac{5}{2x+1} dfrac{1}{2}text{}dfrac{x+1}{3x} dfrac{-3}{x+1}text{}dfrac{4}{2-2x}
Đọc tiếp
\(\dfrac{-7}{x}\text{=}\dfrac{-21}{x-34}\) \(\dfrac{4-x}{-5}\text{=}\dfrac{-5}{4-x}\)
\(\dfrac{3}{x+2}\text{=}\dfrac{5}{2x+1}\) \(\dfrac{1}{2}\text{=}\dfrac{x+1}{3x}\)
\(\dfrac{-3}{x+1}\text{=}\dfrac{4}{2-2x}\)
Tìm x, biết:
a) \(\left(3\dfrac{1}{2}+2x\right).2\dfrac{2}{3}=5\dfrac{1}{3}\)
b) \(\left(2x+3\right)=5\)
c) \(\dfrac{x-2}{4}=\dfrac{5+x}{3}\)
28 tháng 2 2022 lúc 15:04
Tìm x biết:
\(a,\left(x-\dfrac{3}{4}\right)+50\%=\dfrac{1}{6}\)
\(b,\dfrac{1}{2}x-\dfrac{5}{6}x=\dfrac{7}{2}\)
\(c,\left(4-x\right)\left(3x+5\right)=0\)
\(d,\dfrac{x}{16}=\dfrac{50}{32}\)
\(e,\left(2x-3\right)+\dfrac{3}{2}=-\dfrac{1}{4}\)
B1: Tìm x:
1/ \(\dfrac{x+3}{15}\) = \(\dfrac{1}{3}\) - \(\dfrac{1}{15}\)
2/ (2x - 5) = (x - 3) = 0
3/ (3x - 4) - (2x - 5) = 3
4/ (2x + 1) x (\(\dfrac{1}{2}\)x - 1) = 0