Question

llx-2l+3l=5 tìm x

Answer 1

`-> |x-2| = 2`

`x >=2 -> x - 2 =2 -> x = 4`

`x < 2 -> 2 - x = 2 -> x = 0`

Answer 2

=>|x-2|+3=5

=>|x-2|=2

=>x-2= 2hoặc x-2=-2

=>x=4 hoặc x=0

Answer 3

\(\Leftrightarrow\left|x-2\right|+3=5\)

\(\Leftrightarrow\left|x-2\right|=2\)

\(\Leftrightarrow\left[{}\begin{matrix}x-2=-2\\x-2=2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=4\end{matrix}\right.\)