Question

Llmm hộ em với ạ

Answer 1

Gọi số mol K, Ba, K₂O là a, b, c

=> 39a + 137b + 94c = 15,61 (1)

PTHH: 2K + 2H₂O --> 2KOH + H₂

_____a---------------->a----->0,5a

Ba + 2H₂O --> Ba(OH)₂ + H₂

b---------------->b--------->b

K₂O + H₂O --> 2KOH

c---------------->2c

=> 0,5a + b = \(\dfrac{2,016}{22,4}=0,09\left(mol\right)\) (2)

PTHH: Ba(OH)₂ + CO₂ --> BaCO₃ + H₂O

_______b--------->b--------->b

2KOH + CO₂ --> K₂CO₃ + H₂O

(a+2c)->(0,5a+c)->(0,5a+c)

K₂CO₃ + CO₂ + H₂O --> 2KHCO₃

(0,5a+c)->(0,5a+c)

=> \(\left\{{}\begin{matrix}b=\dfrac{V}{22,4}\\b+\left(a+2c\right)=\dfrac{V+4,48}{22,4}\end{matrix}\right.\)

=> a + 2c = 0,2 (3)

=> \(\left\{{}\begin{matrix}a=0,08\\b=0,05\\c=0,06\end{matrix}\right.\)

=> \(\left\{{}\begin{matrix}n_{KOH}=0,2\left(mol\right)\\n_{Ba\left(OH\right)_2}=0,05\left(mol\right)\end{matrix}\right.\)