Bài 2 :
Theo ĐLBTKL
\(m_{Fe}+m_{HCl}=m_{FeCl_2+}m_{H_2}\\ =>m_{HCl}=25,8-11,2=14,6\left(g\right)\)
\(Bài.1:\\ PTHH:2Mg+O_2\underrightarrow{t^o}2MgO\)
\(Áp.dụng.ĐLBTKL,ta.có:\\ m_{Mg}+m_{O_2}=m_{MgO}\\ \Rightarrow m_{O_2}=m_{MgO}-m_{Mg}=2,5-1,5=1\left(g\right)\)
\(Bài.2:\\ PTHH:Fe+2HCl\rightarrow FeCl_2+H_2\\ Áp.dụng.ĐLBTKL,ta.có:\\ m_{Fe}+m_{HCl}=m_{FeCl_2}+m_{H_2}\)
\(\Rightarrow m_{HCl}=m_{FeCl_2}+m_{H_2}-m_{Fe}=25,4+0,4-11,2=14,6\left(g\right)\)
Bài 1 :
Theo ĐLBTKL
\(m_{Mg}+m_{O_2}=m_{MgO}\\ =>m_{O_2}=2,5-1,5=1\left(g\right)\)
H2 + O2 to H2O
