\(a.M=x^2+6x-5\\ x^2+2\cdot3\cdot x+9-14\\ =\left(x+3\right)^2-14\ge-14\\ \Rightarrow GTNN\left(M\right)=-14\Leftrightarrow x+3=0\Rightarrow x=-3\)
câu b thấy thiếu thiếu x . y
\(x-y=2\\ \Rightarrow\left(x-y\right)^2=4\\ \Rightarrow x^2-2xy+y^2=4\\ \Rightarrow34-2xy=4\Rightarrow2xy=30\Rightarrow xy=15\)
Ta có :
\(x^3-y^3=\left(x-y\right)\left(x^2+xy+y^2\right)=2\left(34+15\right)=2\cdot49=98\)