\(\dfrac{a^2-64}{3a-9}.\dfrac{3-a}{8-a}\)
\(=\dfrac{a^2-8^2}{3\left(a-3\right)}.\dfrac{a-3}{a-8}\)
\(=\dfrac{\left(a+8\right)\left(a-8\right)}{3\left(a-3\right)}.\dfrac{a-3}{a-8}\)
\(=\dfrac{\left(a+8\right)\left(a-8\right)\left(a-3\right)}{3\left(a-3\right)\left(a-8\right)}\)
\(=\dfrac{a+8}{3}\)