a: \(A=\left(-2\right)\cdot x^2y\cdot\dfrac{1}{2}xy\)
\(=\left(-2\cdot\dfrac{1}{2}\right)\cdot\left(x^2\cdot x\right)\cdot\left(y\cdot y\right)=-x^3y^2\)
Thay x=-2;y=1/2 vào A, ta được:
\(A=-\left(-2\right)^3\cdot\left(\dfrac{1}{2}\right)^2\)
\(=-\left(-8\right)\cdot\dfrac{1}{4}\)
\(=\dfrac{8}{4}=2\)
b: \(B=xyz\left(-0,5\right)y^2z\)
\(=-0,5\cdot x\cdot y\cdot y^2\cdot z\cdot z\)
\(=-0,5xy^3z^2\)
Thay x=4;y=0,5;z=2 vào B, ta được:
\(B=-0,5\cdot4\cdot0,5^3\cdot2^2\)
\(=-2\cdot0,125\cdot4\)
\(=-8\cdot0,125=-1\)