\(2^{3x+2}=4^{x+5}\)
\(\Rightarrow2^{3x+2}=2^{2x+10}\)
\(\Rightarrow3x+2=2x+10\Rightarrow x=8\)
a, \(\left|x+\dfrac{3}{4}\right|=\dfrac{5}{7}\\ \Rightarrow\left[{}\begin{matrix}x+\dfrac{3}{4}=-\dfrac{5}{7}\\x+\dfrac{3}{4}=\dfrac{5}{7}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-\dfrac{41}{28}\\x=-\dfrac{1}{28}\end{matrix}\right.\)
b, \(2^{3x+2}=4^{x+5}\\ \Rightarrow2^{3x+2}=2^{2x+10}\\ \Rightarrow3x+2=2x+10\\ \Rightarrow x=8\)
=>23x+2=(22)x+5
=>23x+2=22x+10
=>3x+2=2x+10
=>3x-2x=10-2
=>x=8