Question

Làm bài 1b vs 2b cho mik nhé

Answer 1

1B:

a: ΔDEF=ΔQPR

b: 

DE=PQ; FE=QR

=>ΔDEF=ΔPQR

c: \(\widehat{P}=\widehat{D};\widehat{Q}=\widehat{F}\)

=>ΔPQR=ΔDFE

2B:

a: Xét ΔABC có \(\widehat{A}+\widehat{B}+\widehat{C}=180^0\)

=>\(\widehat{C}+30^0+40^0=180^0\)

=>\(\widehat{C}=180^0-70^0=110^0\)

Xét ΔDEF có \(\widehat{D}+\widehat{E}+\widehat{F}=180^0\)

=>\(\widehat{E}=180^0-110^0-30^0=40^0\)

b: Xét ΔABC và ΔDEF có

AB=DE

BC=EF

AC=DF

Do đó: ΔABC=ΔDEF