1,5 tấn = 1500 kg
\(\rightarrow n_{\left(NH_2\right)_2CO}=\dfrac{1500}{60}=25\left(kmol\right)\\ \rightarrow n_N=2.25=50\left(mol\right)\\ \rightarrow m_N=50.14=700\left(kg\right)\)
ta có :\(n_{\left(NH_2\right)_{2^{ }}CO}=\dfrac{1500}{60}=25\left(kmol\right)\)
\(\Rightarrow n_N=25.2=50\left(mol\right)\)
\(\Rightarrow m_N=50.14=700\left(kg\right)\)