\(\int\limits^{\frac{\pi}{3}}_0\frac{tanxdx}{\sqrt{1-ln^2\left(cosx\right)}}\)
\(\int\limits^{pi/2}_0\frac{sinx}{\left(sinx+\sqrt{3}cosx\right)^2}dx\)
Chỉ mình câu tích phân này với !!
\(\int\limits^{pi/2}_0\left(\frac{1}{cos^2\left(sinx\right)}-tan^2\left(cosx\right)\right)dx\)
\(\int\limits^{\frac{\pi}{6}}_0\frac{1}{cosx.cos\left(x+\frac{pi}{4}\right)}dx\)
\(\int\limits^{\frac{\pi}{4}}_0\left(tan^2x+tanx\right).e^xdx\)
\(\int\limits^{ln\sqrt{3}}_0\frac{dx}{e^x+e^{-x}}\)
\(\int\limits^{e^2}_e\left(\frac{1}{ln^2x}-\frac{1}{lnx}\right)dx\)
\(\int\limits^1_{\frac{\sqrt{3}}{3}}\frac{\sqrt{\left(1+x^2\right)^5}}{x^8}dx\)
\(\int\limits^{\frac{\Pi}{3}}_{\frac{\Pi}{4}}\frac{1}{sin^2xcos^2x}dx\)