THam khảo:
https://hoc24.vn/hoi-dap/tim-kiem?id=257988&q=H%C3%B2a%20tan%2016%2C25%20gam%20kim%20lo%E1%BA%A1i%20A%20%28%20h%C3%B3a%20tr%E1%BB%8B%202%29%20v%C3%A0o%20dung%20d%E1%BB%8Bch%20HCl%2Cph%E1%BA%A3n%20%E1%BB%A9ng%20k%E1%BA%BFt%20th%C3%BAc%20thu%20%C4%91%C6%B0%E1%BB%A3c%205%2C6%20l%C3%ADt%20khi%20hi%C4%91ro%20%E1%BB%9F%20%C4%91ktc.%20%20a.H%C3%A3y%20x%C3%A1c%20%C4%91%E1%BB%8Bnh%20kim%20lo%E1%BA%A1i%20A.%20%20b.N%E1%BA%BFu%20d%C3%B9ng%20l%C6%B0%E1%BB%A3ng%20kim%20lo%E1%BA%A1i%20tr%C3%AAn%20t%C3%A1c%20d%E1%BB%A5ng%20h%E1%BA%BFt%20v%E1%BB%9Bi%20dung%20d%E1%BB%8Bch%20H2SO4%20th%C3%AC%20thu%20%C4%91%C6%B0%E1%BB%A3c%205%2C04%20l%C3%ADt%20kh%C3%AD%20hi%C4%91ro%20%C6%A1t%20%C4%91ktc.T%C3%ADnh%20hi%E1%BB%87u%20su%E1%BA%A5t%20ph%E1%BA%A3n%20%E1%BB%A9ng.
\(n_{H_2}=\dfrac{5,6}{22,4}=0,25\left(mol\right)\)
PTHH: 2A + 2nHCl ---> 2ACln + nH2
\(\dfrac{0,5}{n}\)<---------------------------0,25
=> \(M_A=\dfrac{16,25}{\dfrac{0,5}{n}}=32,5n\left(\dfrac{g}{mol}\right)\)
Xét n = 2 tm => MA = 32,5.2 = 65 (g/mol)
=> A là Zn
