Question

Helpppppppppppppppppppppppp! Mik tách nhỏ ra r, bn giúp mik vs, mik đg cần gấp

Answer 1

Bài 7:

 \(P=\dfrac{2x^2-6x+x^2+3x-3x^2-3}{\left(x-3\right)\left(x+3\right)}:\dfrac{2x-2-x+3}{x-3}\)

\(=\dfrac{-3\left(x+1\right)}{\left(x+3\right)}\cdot\dfrac{1}{x+1}=\dfrac{-3}{x+3}\)