b: \(Q=x^3+y^3+3xy\left(x^2+y^2\right)+6x^2y^2\left(x+y\right)\)
\(=\left(x+y\right)^3-3xy\left(x+y\right)+3xy\left\lbrack\left(x+y\right)^2-2xy\right\rbrack+6x^2y^2\)
\(=1-3xy+3xy\left(1-2xy\right)+6x^2y^2\)
\(=1-3xy+3xy-6x^2y^2+6x^2y^2\)
=1
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