b: \(B=\dfrac{12}{17}\left(\dfrac{5}{7}+\dfrac{1}{7}+\dfrac{1}{7}\right)=\dfrac{12}{17}\)
\(A=-\dfrac{11}{5}+\left(\dfrac{2}{7}+\dfrac{5}{7}\right)-\left(\dfrac{12}{13}+\dfrac{1}{13}\right)=-\dfrac{11}{5}+1-1=-\dfrac{11}{5}\\ B=\dfrac{12}{17}\left(\dfrac{5}{7}+\dfrac{1}{7}+\dfrac{1}{7}\right)=\dfrac{12}{17}\cdot1=\dfrac{12}{17}\\ C=\left(\dfrac{1}{3}-\dfrac{13}{6}\right)^2:\left(-\dfrac{121}{36}\right)=\left(-\dfrac{11}{6}\right)^2\cdot\left(-\dfrac{6}{11}\right)^2=1^2=1\)