Question

help em vs ạ

Answer 1

\(H=\left(-2\right)^3\cdot\dfrac{-1}{4}+\left(\dfrac{4}{3}-1\dfrac{5}{6}\right):\dfrac{5}{12}\)

\(H=-8\cdot\dfrac{-1}{4}+\left(\dfrac{4}{3}-\dfrac{11}{6}\right)\cdot\dfrac{12}{5}\)

\(H=2+\left(-\dfrac{1}{2}\right)\cdot\dfrac{12}{5}\)

\(H=2+\left(-\dfrac{6}{5}\right)\)

\(H=\dfrac{4}{5}\)