Bài 2:
a: ĐKXĐ: x<>1; x<>-1
b: \(=\dfrac{x}{2\left(x-1\right)}-\dfrac{3}{2\left(x+1\right)}-\dfrac{1}{\left(x-1\right)\left(x+1\right)}\)
\(=\dfrac{x^2+x-3x+3-2}{2\left(x-1\right)\left(x+1\right)}=\dfrac{x^2-2x+1}{2\left(x-1\right)\left(x+1\right)}=\dfrac{x-1}{2\left(x+1\right)}=\dfrac{x-1}{2x+2}\)
c: Để P=2 thì 4x+4=x-1
=>3x=-5
=>x=-5/3