Question

Hấp thụ toàn 13,44l CO2 vào 200ml dd KOH 3M. Tính m muối ?

Answer 1

\(\rightarrow\left\{{}\begin{matrix}K^+:0,6\\CO_3^{2-}:0,6\\\rightarrow H^+:0,6\end{matrix}\right.\rightarrow\left\{{}\begin{matrix}K^+:0,6\\HCO_3^-:0,6\end{matrix}\right.\)

\(\Rightarrow m_{M'}=0,6.39+0,6.61=60\left(g\right)\)

Answer 2

\(n_{CO_2}=\dfrac{13,44}{22,4}=0,6\left(mol\right)\); \(n_{KOH}=3.0,2=0,6\left(mol\right)\)

PTHH: 2KOH + CO₂ --> K₂CO₃ + H₂O

_______0,6--->0,3------->0,3

K₂CO₃ +CO₂ + H₂O --> 2KHCO₃

_0,3--->0,3-------------->0,6

=> m_KHCO3 = 0,6.100 = 60(g)