\(\text{Δ}=\left(m+1\right)^2-4\cdot1\cdot m=m^2+2m+1-4m\)
\(=m^2-2m+1=\left(m-1\right)^2>=0\)
=>Phương trình luôn có hai nghiệm
\(A=\left(x_1-x_2\right)^2=\left(x_1+x_2\right)^2-4x_1x_2\)
\(=\left(m+1\right)^2-4m=\left(m-1\right)^2>=0\forall m\)
Dấu '=' xảy ra khi m-1=0
=>m=1