\(a,\) Mình nghĩ là đề phải là tính N chứ?
\(N=\dfrac{3}{2\left(-5\right)+6}=-\dfrac{3}{4}\\ b,M=\dfrac{x^2-6x+9+3x^2+9x-4x^2-9}{\left(x-3\right)\left(x+3\right)}\\ M=\dfrac{3x}{\left(x-3\right)\left(x+3\right)}\\ c,P=\dfrac{M}{N}=\dfrac{3x}{\left(x-3\right)\left(x+3\right)}\cdot\dfrac{2\left(x+3\right)}{3}=\dfrac{2x}{x-3}\\ P=\dfrac{2\left(x-3\right)+6}{x-3}=2+\dfrac{6}{x-3}\in Z\\ \Rightarrow x-3\inƯ\left(6\right)=\left\{-6;-3;-2;-1;1;2;3;6\right\}\\ \Rightarrow x\in\left\{-3;0;1;2;4;5;6;9\right\}\)
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