a. (x - 5)(x + 2) + (x + 1)(2 - x) = 15
<=> x2 + 2x - 5x - 10 + 2x - x2 + 2 - x = 15
<=> x2 - x2 + 2x + 2x - 5x - x = 3
<=> -2x = 3
<=> \(x=\dfrac{-3}{2}\)
b. (5x - 2)(5x + 2) - (5x + 3)(5x - 4) = 8
<=> 25x2 - 4 - 25x2 + 20x - 15x + 12 = 8
<=> 25x2 - 25x2 + 20x - 15x = 8 + 4 - 12
<=> 5x = 0
<=> x = 0
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