Question

giúp vs ạ

Answer 1

BÀi 2:

\(\frac{1}{x+1}-\frac{1}{x+2}\)

\(=\frac{x+2-\left(x+1\right)}{\left(x+2\right)\left(x+1\right)}\)

\(=\frac{1}{\left(x+1\right)\left(x+2\right)}\)

Bài 1:

a: \(\frac{3x+1}{x+y}-\frac{2x-3}{x+y}\)

\(=\frac{3x+1-2x+3}{x+y}\)

\(=\frac{x+4}{x+y}\)

b: \(\frac{xy}{2x-y}-\frac{x^2}{y-2x}\)

\(=\frac{xy+x^2}{2x-y}\)

c: \(\frac{a+b}{a}-\frac{a}{a-b}-\frac{b^2}{a^2-ab}\)

\(=\frac{\left(a+b\right)\left(a-b\right)-a^2-b^2}{a\cdot\left(a-b\right)}=\frac{a^2-b^2-a^2-b^2}{a\left(a-b\right)}\)

\(=-\frac{2b^2}{a\left(a-b\right)}\)