Question

Giúp với

Answer 1

\(\Leftrightarrow2-x=\left(3-\sqrt{3x+1}\right)^2\)

Answer 2

hihi....sorry...lm tiếp nha

\(\Leftrightarrow2-x=10+3x-6\sqrt{3x+1}\)

\(\Leftrightarrow6\sqrt{3x+1}=8+4x\)

\(\Leftrightarrow3\sqrt{3x+1}=4+2x\)

\(\Leftrightarrow\left(3\sqrt{3x+1}\right)^2=\left(4+2x\right)^2\)

\(\Leftrightarrow9\left(3x+1\right)=16+16x+4x^2\)

\(\Leftrightarrow27x+9=16+16x+4x^2\)

\(\Leftrightarrow4x^2-11x+7=0\)

Answer 3

\(\left[\begin{matrix}x-1=0\\4x-7=0\end{matrix}\right.\Leftrightarrow\left[\begin{matrix}x=1\\x=\frac{7}{4}\end{matrix}\right.\)t/m đk

hihi...quên ko đặt đk:\(x\le2\)

\(x\ge\frac{-1}{3}\)