\(a\left(\sqrt{15}+2\sqrt{3}\right)^2+12\sqrt{5}=15+4\sqrt{45}+12+12\sqrt{5}\)
\(=27+4\sqrt{9.5}+12\sqrt{5}=27+12\sqrt{5}+12\sqrt{5}=27+24\sqrt{5}\)
\(b,2\sqrt{5}\left(2-3\sqrt{5}\right)+\left(1-2\sqrt{5}\right)^2+6\sqrt{5}\)
\(=4\sqrt{5}-30+1-4\sqrt{5}+20+6\sqrt{5}\)
\(=6\sqrt{5}-9\)
Đúng 2
Bình luận (0)
