10:
a: \(=\dfrac{9-18+14}{24}\cdot\dfrac{6}{5}+\dfrac{1}{2}=\dfrac{1}{4}+\dfrac{1}{2}=\dfrac{3}{4}\)
b; \(=\dfrac{1}{2}+\dfrac{3}{4}-\dfrac{3}{4}+\dfrac{4}{5}=\dfrac{1}{2}+\dfrac{4}{5}=\dfrac{13}{10}\)
c: \(=\dfrac{77}{12}:\dfrac{11}{4}+\dfrac{53}{4}\cdot\dfrac{2}{15}\)
\(=\dfrac{77}{12}\cdot\dfrac{4}{11}+\dfrac{53}{30}\)
=41/10
d: \(=\dfrac{1}{8}\cdot\dfrac{4}{3}-\dfrac{2}{7}\cdot\dfrac{49}{4}=\dfrac{1}{6}-\dfrac{7}{2}=\dfrac{1-21}{6}=\dfrac{-20}{6}=-\dfrac{10}{3}\)
f: \(=\dfrac{5}{16}\cdot8-\left(\dfrac{9}{4}-\dfrac{3}{5}\right)\cdot\dfrac{10}{11}\)
=5/2-37/20*10/11
=9/11
Bài 9
a) 1/(2.3) + 1/(3.4) + ... + 1/(99.100)
= 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/99 - 1/100
= 1/2 - 1/100
= 49/100
b) B = 5/(1.4) + 5/(4.7) + ... + 5/(100.103)
= 5/3 . [3/(1.4) + 3/(4.7) + ... + 3/(100.103)]
= 5/3 . (1 - 1/4 + 1/4 - 1/7 + 1/7 + ... + 1/100 - 1/103)
= 5/3 . (1 - 1/103)
= 5/3 . 102/103
= 170/103
