Question

GIÚP MINHF LM Ý C VÓI Ạ

Answer 1

\(P=\dfrac{x}{x-4}+\dfrac{1}{\sqrt{x}-2}+\dfrac{1}{\sqrt{x}+2}\left(x\ge0,x\ne4\right)\)

\(=\dfrac{x}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}+\dfrac{1}{\sqrt{x}-2}+\dfrac{1}{\sqrt{x}+2}\)

\(=\dfrac{x+\sqrt{x}+2+\sqrt{x}-2}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}=\dfrac{x+2\sqrt{x}}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}=\dfrac{\sqrt{x}\left(\sqrt{x}+2\right)}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}\)

\(=\dfrac{\sqrt{x}}{\sqrt{x}-2}\)

c) \(P=\dfrac{4}{3}\Rightarrow\dfrac{\sqrt{x}}{\sqrt{x}-2}=\dfrac{4}{3}\Rightarrow3\sqrt{x}=4\sqrt{x}-8\Rightarrow\sqrt{x}=8\Rightarrow x=64\)