Question

giúp mình vs ạ,mình cần gấp

Answer 1

a: Ta có: \(\left(x-1\right)\left(x^2+x+1\right)-x^3+2\)

\(=x^3-1-x^3+2\)

=1

b: ta có: \(\left(2x-y\right)\left(4x^2+2xy+y^2\right)-8x^3-5\)

\(=8x^3-y^3-8x^3-5\)

\(=-y^3-5\)

c: Ta có: \(\left(x+1\right)\left(x^2-x+1\right)-x^3+2\)

\(=x^3+1-x^3+2\)

=3

d: Ta có: \(\left(2x+y\right)\left(4x^2-2xy+y^2\right)-8x^3-5\)

\(=8x^3+y^3-8x^3-5\)

\(=y^3-5\)

Answer 2

a) \(\left(x-1\right)\left(x^2+x+1\right)-x^3+2=x^3-1-x^3+2=1\)

b) \(\left(2x-y\right)\left(4x^2+2xy+y^2\right)-8x^3-5=8x^3-y^3-8x^3-5=-y^3-5\)

c) \(\left(x+1\right)\left(x^2-x+1\right)-x^3+2=x^2+1-x^3+2=3\)

d) \(\left(2x+y\right)\left(4x^2-2xy+y^2\right)-8x^3-5=8x^3+y^3-8x^3-5=y^3-5\)

e) \(\left(3x+2\right)\left(9x^2-6x+4\right)-27x^3-7=27x^3+8-27x^3-7=1\)

f) \(\left(3x-2\right)\left(9x^2+6x+4\right)-27x^3-7=27x^3-8-27x^3-7=-15\)