\(U=I_AR_2=2R_2\).
Ta có: \(R_N=\dfrac{R_1R_2}{R_1+R_2}=\dfrac{3R_2}{R_2+3}\)
Suy ra: \(I=\dfrac{E}{R_N+r}=\dfrac{18\left(R_2+3\right)}{8R_2+15}\left(1\right)\).
Mặt khác: \(I=\dfrac{U}{R_N}=\dfrac{2\left(R_2+3\right)}{3}\left(2\right)\).
\(\left(1\right),\left(2\right)\) cho ta: \(R_2=1,5\left(\Omega\right)\)
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