Đáp án:
`a,f(x)=3x^3 +4x^2 -2x-1-2x^3`
`=(3x^3-2x^3) +4x^2 -2x-1`
`=x^3 +4x^2 -2x-1`
`b, h(x)=f(x) - g(x)`
`->h(x)=(x^3 +4x^2 -2x-1) - (x^3 +4x^2+3x-2)`
`=x^3+4x^2-2x-1-x^3-4x^2 -3x+2`
`=(x^3-x^3) +(4x^2-4x^2) +(-2x-3x) + (-1+2)`
`= -5x+1`
`c,` Nghiệm của `h(x)=0`
`-> -5x+1=0`
`=> -5x=0-1`
`=>-5x=-1`
`=>x=-1:(-5)`
`=>x=1/5`