Question

Giúp mình với

Answer 1

\(\dfrac{a+b+c}{a+b-c}=\dfrac{a-b+c}{a-b-c}\)

=>\(\left(a+b+c\right)\left(a-b-c\right)=\left(a-b+c\right)\left(a+b-c\right)\)

\(\Leftrightarrow a^2-\left(b+c\right)^2=a^2-\left(b-c\right)^2\)

=>\(\left(b+c\right)^2=\left(b-c\right)^2\)

=>\(\left[{}\begin{matrix}b+c=b-c\\b+c=c-b\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}c=0\left(nhận\right)\\b=0\left(loại\right)\end{matrix}\right.\)