1: \(A=\dfrac{3x^2+2x-2x^2+1}{3x+2}=\dfrac{x^2+2x+1}{3x+2}=\dfrac{\left(x+1\right)^2}{3x+2}\)
Khi x=2 thì \(A=\dfrac{\left(2+1\right)^2}{3\cdot2+1}=\dfrac{9}{7}\)
2: \(B=\dfrac{3x+2-3x+2+3x-6}{\left(3x+2\right)\left(3x-2\right)}=\dfrac{3x-6}{\left(3x+2\right)\left(3x-2\right)}\)