Question

  giúp mình với mình cảm ơn ạ

Answer 1

a: ĐKXĐ: x>=0; x<>9

b: \(=\dfrac{x\sqrt{x}-3x-x\sqrt{x}-3x-\sqrt{x}-3+6x\sqrt{x}}{x-9}:\dfrac{\sqrt{x}-3-\sqrt{x}-3}{\sqrt{x}+3}\)

\(=\dfrac{6x\sqrt{x}-6x-3}{x-9}\cdot\dfrac{\sqrt{x}+3}{-6}\)

\(=\dfrac{-2x\sqrt{x}-2x-1}{2\left(\sqrt{x}-3\right)}\)