Question

giúp mình với ạ

 

Answer 1

a: \(\Leftrightarrow\left(2x+1\right)\left(5x-8-3x+2\right)=0\)

=>(2x+1)(2x-6)=0

=>x=3 hoặc x=-1/2

b: \(\Leftrightarrow\left(2x+1\right)\left(2x-1\right)-\left(2x+1\right)\left(3x-5\right)=0\)

\(\Leftrightarrow\left(2x+1\right)\left(-x+4\right)=0\)

=>x=-1/2 hoặc x=4

c: \(\Leftrightarrow\left(2x-2\right)^2-\left(x+1\right)^2=0\)

\(\Leftrightarrow\left(2x-2-x-1\right)\left(2x-2+x+1\right)=0\)

\(\Leftrightarrow\left(x-3\right)\left(3x-1\right)=0\)

=>x=3 hoặc x=1/3

Answer 2

d)

<=> x(2x²+ 5x – 3) = 0

<=> x.(2x² + 6x – x – 3) = 0

<=> x. [2x(x + 3) – (x + 3)] = 0

<=> x.(2x – 1)(x + 3) = 0

=> x = 0

x = 1/2

x = -3