Question

Giúp mình với ạ

Answer 1

Bài 2: 

a: \(\left(\dfrac{1}{3}x+2\right)\left(3x-6\right)\)

\(=x^2-2x+6x-12\)

\(=x^2+4x-12\)

b: \(\left(2x-3\right)\left(3-4x\right)\)

\(=6x-8x^2-9+12x\)

\(=-8x^2+18x-9\)

Answer 2

\(1,\\ a,=6x^2y^2-12xy^3+9x^2y^3\\ b,=3x^3-2x^2+5x\\ c,=5x+3x^2-3x-3=3x^2+2x-3\\ d,=2x^3y^2+\dfrac{2}{9}x^4y^2-\dfrac{1}{3}x^2y^3\\ e,=3x^5y^3-\dfrac{3}{4}x^4y^2+\dfrac{3}{4}x^3y^7\\ f,=\dfrac{2}{3}x^5y^2+\dfrac{4}{3}x^3+\dfrac{20}{3}xy^2\)