\(A=-x^2-x-\dfrac{1}{4}+\dfrac{1}{4}=-\left(x+\dfrac{1}{2}\right)^2+\dfrac{1}{4}< =\dfrac{1}{4}\)
Dấu '=' xảy ra khi x=-1/2
\(C=5-\left(x-1\right)\left(x+2\right)\)
\(=5-\left(x^2+x-2\right)\)
\(=5-x^2-x+2\)
\(=-x^2-x+7\)
\(=-\left(x^2+x-7\right)\)
\(=-\left(x+\dfrac{1}{2}\right)^2+7.25< =7.25\)
Dấu '=' xảy ra khi x=-1/2