a: \(=\dfrac{10}{7}-\dfrac{10}{7}+\dfrac{1}{4}=\dfrac{1}{4}\)
b: \(=\dfrac{6}{5}\left(\dfrac{19}{11}+\dfrac{36}{11}\right)=\dfrac{6}{5}\cdot5=6\)
c: \(=3\cdot\dfrac{1}{4}-6=\dfrac{3}{4}-\dfrac{24}{4}=-\dfrac{21}{4}\)
\(\text{a)}\dfrac{10}{7}+\left(\dfrac{10}{-7}+0,25\right)\)
\(=\dfrac{10}{7}+\dfrac{10}{-7}+0,25\)
\(=0+0,25=0,25\)
\(\text{b)}\dfrac{19}{11}.\dfrac{6}{5}+\dfrac{36}{11}.\dfrac{6}{5}\)
\(=\dfrac{6}{5}.\left(\dfrac{19}{11}+\dfrac{36}{11}\right)\)
\(=\dfrac{6}{5}.5=6\)
\(\text{c)}3.\left(\dfrac{1}{2}\right)^2-\sqrt{36}\)
\(=3.\dfrac{1}{4}-6\)
\(=\dfrac{3}{4}-6=\dfrac{-21}{4}\)