Question

Giúp mình hai bài này ạ

Answer 1

+) MTC : (2x² + 2x) = 6x² . (x + 1) . (x - 2) : (2x² + 2x) = 3x . (x - 2)

+) MTC : (3x² - 6x) = 6x² . (x + 1) . (x - 2) : (3x² - 6x) = 2x . (x + 1)

 

+) \(\dfrac{1}{2x^2+2x}=\dfrac{1.3x.\left(x-2\right)}{2x.\left(x+1\right).3x.\left(x-2\right)}=\dfrac{3x^2-6x}{6x^2.\left(x+1\right)\left(x-2\right)}\)

+) \(\dfrac{1}{3x^2-6x}=\dfrac{1.2x.\left(x+1\right)}{3x.\left(x-2\right).2x.\left(x+1\right)}=\dfrac{2x^2+2x}{6x^2.\left(x+1\right).\left(x-2\right)}\)