d: \(=\dfrac{5^3}{5\cdot10^2}=\dfrac{1}{2^2}=\dfrac{1}{4}\)
e: \(=\dfrac{-7\cdot3+4\cdot6}{\left(-5\right)\cdot3-2\cdot3}=\dfrac{3\cdot\left(-7+4\cdot2\right)}{3\cdot\left(-7\right)}=\dfrac{1}{-7}=-\dfrac{1}{7}\)
f: \(=\dfrac{-17\left(13-2\right)}{-11\cdot11}=\dfrac{-17\cdot11}{-11\cdot11}=\dfrac{17}{11}\)
\(d,\dfrac{5.5^2}{9.10^2-4.10^2}=\dfrac{5^3}{\left(2.5\right)^2\left(9-5\right)}=\dfrac{5.5^2}{2^2.5^2.5}=\dfrac{1}{4}\)
\(e,\dfrac{\left(-7\right).3-4.\left(-6\right)}{\left(-5\right).3-2.3}=\dfrac{\left(-21\right)-\left(-24\right)}{3\left(-5-2\right)}=\dfrac{3}{3.\left(-7\right)}=-\dfrac{1}{7}\)
\(f,\dfrac{\left(-17\right).13+17.2}{-11.2-11.9}=\dfrac{17.\left(-13\right)+17.2}{-11\left(2+9\right)}=\dfrac{17\left(-13+2\right)}{-11.11}=\dfrac{17\left(-11\right)}{11\left(-11\right)}=\dfrac{17}{11}\)
