Question

giúp mình câu a với ạ !!!

Answer 1

\(M_{Na_3PO_4}=23.3+31+16.4=164\left(\dfrac{g}{mol}\right)\)

\(\%Na=\dfrac{23.3}{164}.100\%=42\%\)

\(\%P=\dfrac{31}{164}.100\%=18,9\%\)

\(\%O=100\%-42\%-18,9\%=39,1\%\)