Question

  giúp mình câu 2 với

Answer 1

Bài 2:

a: \(3x-\dfrac{1}{3}=\sqrt{\dfrac{25}{9}}\)

=>\(3x-\dfrac{1}{3}=\dfrac{5}{3}\)

=>\(3x=\dfrac{5}{3}+\dfrac{1}{3}=\dfrac{6}{3}=2\)

=>\(x=\dfrac{2}{3}\)

b: \(\left(2x-2\right)-3,75=0,25\)

=>2x-2=0,25+3,75=4

=>2x=6

=>x=3