Question

  giúp mình bài này với

Answer 1

a+b+c=0

=>\(\left(a+b+c\right)^2=0\)

=>\(a^2+b^2+c^2+2\left(ab+bc+ac\right)=0\)

=>\(a^2+b^2+c^2=0\)

=>a=b=c=0

\(A=\left(a-1\right)^{2023}+b^{2024}+\left(c+1\right)^{2025}\)

\(=\left(0-1\right)^{2023}+0^{2024}+\left(0+1\right)^{2025}\)

\(=\left(-1\right)^{2023}+0+1^{2025}\)

=-1+0+1

=0