Question

giúp mình bài 5, 6 ạ

Answer 1

6:

1: \(A=\dfrac{2x-6\sqrt{x}+\sqrt{x}+3-2x+3\sqrt{x}-9}{x-9}\)

\(=\dfrac{-2\sqrt{x}-6}{x-9}=\dfrac{-2}{\sqrt{x}-3}\)

2: A=4/5

=>-2/căn x-3=4/5

=>căn x-3=-2*5/4=-10/4=-5/2

=>căn x=1/2

=>x=1/4

3: A-1=0

=>A=1

=>căn x-3=-2

=>căn x=1

=>x=1