`1)sqrt{4x-4}-3=7`
`đk:4x-4>=0<=>x>=1`
`pt<=>sqrt{4x-4}=10`
BP 2 vế ta có:
`4x-4=100`
`<=>4x=104`
`<=>x=26(tm)`
Vậy `S={26}`
`4)sqrt{3x+1}-sqrt{x-1}=2`
`đk:x>=1`
`pt<=>sqrt{3x+1}=2+sqrt{x-1}`
BP 2 vế ta có:
`3x+1=x-1+4+4sqrt{x-1}`
`<=>3x+1=x+3+4sqrt{x-1}`
`<=>4sqrt{x-1}=2x-2`
`<=>2sqrt{x-1}=x-1`
`<=>sqrt{x-1}(sqrt{x-1}-2)=0`
`+)sqrt{x-1}=0<=>x=1`
`+)sqrt{x-1}=2<=>x=5`
Vậy `S={1,5}`