Question

Giúp mik vs mn

Answer 1

1) C + O₂ --t^o--> CO₂

2) \(n_{O_2}=\dfrac{6,4}{32}=0,2\left(mol\right)\)

PTHH: C + O₂ --t^o--> CO₂

_____0,2<-0,2------->0,2

=> m_C = 0,2.12 = 2,4 (g)

3) V_CO2 = 0,2.24,79 = 4,958(l)