Question

giúp mik với nhé mn

\(A=\frac{x}{\sqrt{x}-1}+\frac{\sqrt{x}-2x}{x-\sqrt{x}}\)            với x>0;  x khác 1

Answer 1

\(A=\frac{x}{\sqrt{x}-1}+\frac{\sqrt{x}-2x}{x-\sqrt{x}}\)

\(=\frac{x}{\sqrt{x}-1}+\frac{1-2\sqrt{x}}{\sqrt{x}-1}=\frac{x-2\sqrt{x}+1}{\sqrt{x}-1}=\frac{\left(\sqrt{x}-1\right)^2}{\sqrt{x}-1}=\sqrt{x}-1\)

Answer 2

bn làm tắt à

Answer 3

\(A=\dfrac{x}{\sqrt{x}-1}+\dfrac{\sqrt{x}\left(1-2\sqrt{x}\right)}{\sqrt{x}\left(\sqrt{x}-1\right)}=\dfrac{x}{\sqrt{x}-1}+\dfrac{1-2\sqrt{x}}{\sqrt{x}-1}\)

\(=\dfrac{x-2\sqrt{x}+1}{\sqrt{x}-1}=\dfrac{\left(\sqrt{x}-1\right)^2}{\sqrt{x}-1}=\sqrt{x}-1\)