Question

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Answer 1

\(=-\dfrac{5}{7}\times\left(\dfrac{2}{11}+\dfrac{9}{11}\right)+\dfrac{5}{7}=-\dfrac{5}{7}+\dfrac{5}{7}=0\)

Answer 2

\(=\dfrac{5}{7}\cdot\dfrac{-2}{11}+\dfrac{5}{7}\cdot\dfrac{-9}{11}+\dfrac{5}{7}\cdot1\\ =\dfrac{5}{7}\left(\dfrac{-2}{11}+\dfrac{-9}{11}+1\right)=\dfrac{5}{7}\cdot0=0\)

Answer 3

\(\dfrac{-5}{7}\cdot\dfrac{2}{11}+\dfrac{-5}{7}\cdot\dfrac{9}{11}+\dfrac{5}{7}\)

\(=\dfrac{-5}{7}\left(\dfrac{2}{11}+\dfrac{9}{11}\right)\)

\(\dfrac{-5}{7}\cdot1=\dfrac{-5}{7}\)

Answer 4

\(\dfrac{-5}{7}\cdot\dfrac{2}{11}+\dfrac{-5}{7}\cdot\dfrac{9}{11}+\dfrac{5}{7}\)

\(=\dfrac{5}{7}\cdot\dfrac{-2}{11}+\dfrac{5}{7}\cdot\dfrac{-9}{11}+\dfrac{5}{7}+1\)

\(=\dfrac{5}{7}\cdot\left(\dfrac{-2}{11}+\dfrac{-9}{11}+1\right)\)

\(=\dfrac{5}{7}\cdot\text{ }\)[ (-1) +1 ]

\(=\dfrac{5}{7}\cdot0=\dfrac{5}{7}\)